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一、Seven different numbers are selected from the integers 1 to 100, and each number is divided by 7. What is the sum of the remainders?

(1)The range of the seven remainders is 6.

(2)The seven numbers selected are consecutive integers.

A Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

B Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.

C BOTH statement TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

D EACH statement ALONE is sufficient.

E Statements (1) and (2) TOGETHER are NOT sufficient.

正确答案：B

解题思路：

从7-100的数中，除7余数始终为0-6的循环。

条件1：符合条件的可以先取两个余数分别为0和6的，剩下的数可以随便取，所以结果不确定，not sufficient。

条件2：任何连续的7个数除7的余数和一定等于0+1+2+3+4+5+6，所以sufficient。

二、A grocer has 400 pounds of coffee in stock, 20 percent of which is decaffeinated. If the grocer buys another 100 pounds of coffee of which 60 percent is decaffeinated, what percent, by weight, of the grocer’s stock of coffee is decaffeinated?

A 28%

B 30%

C 32%

D 34%

E 40%

正确答案：A

解题思路：

400*20%+100*60%=140

140/(400+100)=28%

三、If k is a positive integer, is k the square of an integer?

(1) k is divisible by 4.

(2) k is divisible by exactly 4 different prime numbers.

A Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

B Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.

C BOTH statement TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

D EACH statement ALONE is sufficient.

E Statements (1) and (2) TOGETHER are NOT sufficient.

正确答案：E

题目分析：

求K是否是一个整数的平方数。

详细解法：

条件(1)， K能被4整除。

如果K=16，是4的平方数， 如果K=8,不是平方数，所以不充分。

条件(2)， K能被正好4个质数整除。

最小的4个质数乘积=2*3*5*7=210

如果K=210， 不是平方数， 如果K=210*210， 是平方数， 所以也不充分。

(1)+(2)相加也不充分。

所以选E。

四、The average (arithmetic mean) of the 5 positive integers k, m, r, s, and t is 16, and k < m < r < s < t. If t is 40, what is the greatest possible value of the median of the 5 integers?

A 16

B 18

C 19

D 20

E 22

正确答案：B

解题思路：

首先5个数的sum是16*5=80，t=40，所以说剩下4个sum是40，r是中数，要使得r最大，那么s应该是r+1，而k和m应该是1和2(题目说他们都是positive的)，这样算下来max of "r"就是18。

五、In June 1989, what was the ratio of the number of sales transactions made by Salesperson X to the number of sales transactions made by Salesperson Y?

(1) In June 1989, Salesperson X made 50 percent more sales transactions than Salesperson Y did in May 1989.

(2) In June 1989, Salesperson Y made 25 percent more sales transactions than in May 1989.

A Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

B Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.

C BOTH statement TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

D EACH statement ALONE is sufficient.

E Statements (1) and (2) TOGETHER are NOT sufficient.

正确答案：C

解题思路：

本题的出题点在于对数学题完全文字化后的转化理解能力和对月份细节的注意上。

这道题求6月销售员X和Y之间销售额的比值。

条件1：销售员X在6月的销售额比销售员Y在5月的销售额多50%。

条件2：销售员Y在6月销售额比自己在5月的销售额多25%。

两个条件单独看都无法得出X和Y之间在6月的直接比值。但结合在一起则可以间接的计算出来。因此选择C。

好了，以上就是2020年GMAT考试《GMAT数学》每日一练（9）的全部内容了，如果各位小伙伴还有不明白的地方，可以进入帮考网咨询了解哦！